(New page: == Define a CT Signal and its Fourier Series Coefficients == Periodic CT Signal: x(t) = 5cos(6t) + 2sin(3t) = <math> 5 * \frac {e^{j6t} + e^{-j6t}}{2} + 2 * \frac {e^{j3t} - e^{-j3t}}...) |
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+ | [[Category:problem solving]] | ||
+ | [[Category:ECE301]] | ||
+ | [[Category:ECE]] | ||
+ | [[Category:Fourier series]] | ||
+ | [[Category:signals and systems]] | ||
+ | |||
+ | == Example of Computation of Fourier series of a CT SIGNAL == | ||
+ | A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]] | ||
+ | ---- | ||
== Define a CT Signal and its Fourier Series Coefficients == | == Define a CT Signal and its Fourier Series Coefficients == | ||
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e^{-j3t} </math> | e^{-j3t} </math> | ||
− | = | + | '''<math>a1 = \frac {5}{2}</math>''' |
+ | |||
+ | '''<math>a-1 = \frac{5}{2}</math>''' | ||
+ | |||
+ | == a2= a-2 = j == | ||
+ | ---- | ||
+ | [[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]] |
Latest revision as of 10:05, 16 September 2013
Example of Computation of Fourier series of a CT SIGNAL
A practice problem on "Signals and Systems"
Define a CT Signal and its Fourier Series Coefficients
Periodic CT Signal: x(t) = 5cos(6t) + 2sin(3t)
= $ 5 * \frac {e^{j6t} + e^{-j6t}}{2} + 2 * \frac {e^{j3t} - e^{-j3t}}{2j} $
= $ \frac{5}{2} * e^{j6t} - \frac{5}{2} * e^{-j6t} + j * e^{j3t} -j* e^{-j3t} $
$ a1 = \frac {5}{2} $
$ a-1 = \frac{5}{2} $