(CT Periodic Signal)
 
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[[Category:problem solving]]
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[[Category:ECE301]]
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[[Category:ECE]]
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[[Category:Fourier series]]
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[[Category:signals and systems]]
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== Example of Computation of Fourier series of a CT SIGNAL ==
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A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]]
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----
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==CT Periodic Signal==
 
==CT Periodic Signal==
:<math>x(t)=2cos(\pi t)+3 \,</math>
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:<math>x(t)=2cos(\pi/2 t)+3 \,</math>
:<math>T=\dfrac{2\pi}{\pi} \,</math>
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:<math>T=\dfrac{2\pi}{4} \,</math>
:<math>T=2 \,</math>
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:<math>T=\pi/2 \,</math>
:<math>x(t)=\dfrac{e^{ j t \pi}-e^{- j t \pi}}{2}+3</math>
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:<math>x(t)=2\dfrac{e^{.5 j t \pi}-e^{-.5 j t \pi}}{2}+3</math>
:<math>x(t)=e^{ j t \pi}-e^{- j t \pi}+3e^{ \pi*0} \, </math>
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:<math>x(t)=e^{.5 j t \pi}-e^{-.5 j t \pi}+3e^{.5 \pi*0} \, </math>
 
<pre>
 
<pre>
a-1=1/2
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a-1=1
 
a0=3
 
a0=3
a1=1/2
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a1=1
 
a2=0
 
a2=0
 
a3=0
 
a3=0
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----
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[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

Latest revision as of 09:57, 16 September 2013

Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


CT Periodic Signal

$ x(t)=2cos(\pi/2 t)+3 \, $
$ T=\dfrac{2\pi}{4} \, $
$ T=\pi/2 \, $
$ x(t)=2\dfrac{e^{.5 j t \pi}-e^{-.5 j t \pi}}{2}+3 $
$ x(t)=e^{.5 j t \pi}-e^{-.5 j t \pi}+3e^{.5 \pi*0} \, $
a-1=1
a0=3
a1=1
a2=0
a3=0
----
[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

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