(One intermediate revision by the same user not shown)
Line 3: Line 3:
 
[[Category:math]]
 
[[Category:math]]
 
[[Category:discrete math]]
 
[[Category:discrete math]]
[[Category:lecture notes]]
+
[[Category:problem solving]]
  
=[[MA375]]: solution to a homework problem from this week or last week's homeworks=
+
=[[MA375]]: [[MA_375_Spring_2009_Walther_Week_5|Solution to a homework problem from this week or last week's homework]]=
 
Spring 2009, Prof. Walther
 
Spring 2009, Prof. Walther
 
----
 
----

Latest revision as of 08:20, 20 May 2013


MA375: Solution to a homework problem from this week or last week's homework

Spring 2009, Prof. Walther


Question

What is the probability of each outcome when a loaded die is rolled, if 3 is twice as likely to appear as each of the other five numbers on the die


Answer

Well the probability of 3 is twice as likely. So we set up an equation that is equal to 1 because that is the probability of any answer. So, 2x +5x = 1 is the equation. So solve for a and you get 1/7 probability of rolling 1,2,4,5,6 and since 3 is twice as likely you get 2*1/7 which equals 2/7


Back to MA375, Spring 2009, Prof. Walther

Alumni Liaison

To all math majors: "Mathematics is a wonderfully rich subject."

Dr. Paul Garrett