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In general, the Jacobian Matrix of a Transformation F, looks like this: | In general, the Jacobian Matrix of a Transformation F, looks like this: | ||
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To help illustrate this, let's do an example: | To help illustrate this, let's do an example: | ||
Revision as of 08:52, 8 May 2013
Contents
Jacobians and their applications
by Joseph Ruan
Basic Definition
The Jacobian Matrix is just a matrix that takes the partial derivatives of each element of a transformation (which is in the form of a vector. Let T be a transformation such that
$ T(u,v)=<x,y> $
then the Jacobian matrix of this function would look like this:
$ J(u,v)=\begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} $
In general, the Jacobian Matrix of a Transformation F, looks like this:
To help illustrate this, let's do an example:
===Example #1:=== Let's take the Transformation: $ T(u,v) = <u * \cos v,r * \sin v> $ .
What would be the Jacobian Matrix of this Transformation?
Solution:
$ x=u*\cos v \longrightarrow \frac{\partial x}{\partial u}= \cos v , \; \frac{\partial x}{\partial v} = -u*\sin v $
$ y=u*\sin v \longrightarrow \frac{\partial y}{\partial u}= \sin v , \; \frac{\partial y}{\partial v} = u*\cos v $
Therefore the Jacobian matrix is
$ \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix}= \begin{bmatrix} \cos v & -u*\sin v \\ \sin v & u*\cos v \end{bmatrix} $
This example actually showcased the transformation "T" as the change from polar coordinates into Cartesian coordinates.
Let's do another example.
===Example #2:=== Let
Application: Jacaobian Determinants
The determinant of Example #1 gives:
$ \left|\begin{matrix} \cos v & -u * \sin v \\ \sin v & u * \cos v \end{matrix}\right|=~~ u \cos^2 v + u \sin^2 v =~~ u $
Notice that, in an integral when changing from cartesian coordinates (dxdy) to polar coordinates $ (drd\theta) $, the equation is as such:
$ dxdy=r*drd\theta $
in this case, since $ u =r $ and $ v = \theta $, then
$ dxdy=u*dudv $
It is easy to extrapolate, then, that the transformation from one set of coordinates to another set is merely
$ dC1=det(J(T))dC2 $
where C1 is the first set of coordinates, det(J(C1)) is the determinant of the Jacobian matrix made from the Transformation T, T is the Transformation from C1 to C2 and C2 is the second set of coordinates.
It is important to notice several aspects: first, the determinant is assumed to exist and be non-zero, and therefore the Jacobian matrix must be square and invertible.
For integrals, changing variables is quite useful. The most obvious case is that of u-substitution. However, for larger dimensions, this gets slightly trickier. Suppose we wanted to change
