Line 11: Line 11:
 
===Basic Definition===
 
===Basic Definition===
  
The Jacobian Matrix is just a matrix that takes the partial derivatives of each element of a function (which is in the form of a vector. So, if F is a function that maps from < u , v > to < x , y >, then the Jacobian of this function would looks like this:
+
The Jacobian Matrix is just a matrix that takes the partial derivatives of each element of a function (which is in the form of a vector. Let F be a function such that
  
<math>\begin{bmatrix}
+
<math>F(u,v)=<x,y> </math>
 +
 
 +
then the Jacobian matrix of this function would look like this:
 +
 
 +
<math>J(u,v)=\begin{bmatrix}
 
\frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\
 
\frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\
 
\frac{\partial y}{\partial u} & \frac{\partial y}{\partial v}  \end{bmatrix}</math>
 
\frac{\partial y}{\partial u} & \frac{\partial y}{\partial v}  \end{bmatrix}</math>
Line 41: Line 45:
  
 
Now after doing
 
Now after doing
 +
 +
 +
 +
----
 +
<div style="font-family: Verdana, sans-serif; font-size: 14px; text-align: justify; width: 70%; margin: auto; border: 1px solid #aaa; padding: 2em;">

Revision as of 08:17, 8 May 2013


Jacobians

This page is dedicated to explaining what the Jacobian matrix is, and also how to use it. In general, this topic is useful for Vector Calculus and making some surface integrals easier to do.

Basic Definition

The Jacobian Matrix is just a matrix that takes the partial derivatives of each element of a function (which is in the form of a vector. Let F be a function such that

$ F(u,v)=<x,y> $

then the Jacobian matrix of this function would look like this:

$ J(u,v)=\begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix} $

To help illustrate this, let's do an example:

Example #1) Let's take the Transformation: $ T(u,v) = <u*\cos v,r*\sin v>. $ What would be the Jacobian Matrix of this Transformation?

Solution: Note that $ x=u*\cos v \longrightarrow \frac{\partial x}{\partial u}= \cos v and \frac{\partial x}{\partial v} = -u*\sin v y=u*\sin v \longrightarrow \frac{\partial y}{\partial u}= \sin v and \frac{\partial y}{\partial v} = u*\cos v $

Therefore the Jacobian matrix is

$ \begin{bmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{bmatrix}= \begin{bmatrix} \cos v & -u*\sin v \\ \sin v & u*\cos v \end{bmatrix} $

Now after doing



Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009