| Line 15: | Line 15: | ||
Problem 2 | Problem 2 | ||
<br> | <br> | ||
| − | a. | + | a. F(unit circle must be in ROCK) |
<br> | <br> | ||
b. F | b. F | ||
<br> | <br> | ||
| − | c. | + | c. T F(cause of the square root) T F |
<br> | <br> | ||
| − | d. | + | d. F(ak=a*-k) T(a-k = ak) |
<br> | <br> | ||
e. F | e. F | ||
Revision as of 05:35, 3 May 2013
Problem 1
a1. by using integral over function square E = 6 so P = 0
a2. P = 6 / N so P is infinite
b. N must less than L + M - 1
c. 2*PI/T greater than 20000PI
so that T <= 1/10000
d. We did not cover the material
Problem 2
a. F(unit circle must be in ROCK)
b. F
c. T F(cause of the square root) T F
d. F(ak=a*-k) T(a-k = ak)
e. F
Problem 3:
a.m = K/A
b&c y(t) can be rewritten into 2 parts and has an energy of A^2/2 +k^2/32\t
