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Subset T S (without middle bar)
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as opposed to elements S
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Universal set = the set of all objects considered(context specific)
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Given S
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S
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Set operations 
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complement S = {| S}
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union T  S =  {x|xor x}
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S= ...
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intersection
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T S = {|}
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Note: this is the first of many pages to be uploaded.  
 
Note: this is the first of many pages to be uploaded.  
 
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Revision as of 02:13, 15 April 2013

Subset T S (without middle bar) as opposed to elements S

Universal set = the set of all objects considered(context specific)

Given S S

Set operations  complement S = {| S}



union T S = {x|xor x}


S= ...




intersection

T S = {|}

Note: this is the first of many pages to be uploaded.



1/9/13

If S is discrete and finite S = {$ s_1,s_2,s_3 $} S = {head,tail}, S = {win, lose}, S = {1,2,3,4,5,6}

If S is discrete but infinite,

S = {$ s_1,s_2,s_3 $,...} ex. S = {1,2,3,4,...}

    S = {sin(2$ \pi $*440t),sin(2$ \pi $*880t),sin(2$ \pi $*1320t),...}
    Observe $ _{S = \mathbb{R}} $ is not routable; S = [0,1] is not routable
    S = {sin(2$ \pi $*f*t)} f $ \in \mathbb{R} \geq $ 0 
      = {sin(2$ \pi $*f*t)|0$ \leq f < \infty $}

$ \mathbb{Z} $ is all integers $ -\infty $ to $ \infty $

Is $ \mathbb{Z} $ routable? yes.

  $ \mathbb{Z} $={0,1,-1,2,-2,3,-3, }as opposed to $ \mathbb{R} $

$ \mathbb{R} $= {0,3,e,$ \pi $,-1,1.14,$ \sqrt{2} $}

Many different ways to write a set [0,1] = {x $ \in \mathbb{R} $such that(s. t.) 0$ \leq x \leq $ 1} ={real positive numbers no greater than 1 as well as 0}

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett