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I'm a little rusty on my cards understanding, so hopefully I got the numbers in the right order. | I'm a little rusty on my cards understanding, so hopefully I got the numbers in the right order. | ||
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| + | ==Comments== | ||
| + | *Congratulations on being the first one to dare posting something on this topic! -pm | ||
| + | *Where does the concept of conditional probability come up? | ||
| + | **Answer here. | ||
| + | *I think independence also comes up in this problem. | ||
[[Bonus_point_1_ECE302_Spring2012_Boutin|Back to first bonus point opportunity, ECE302 Spring 2013]] | [[Bonus_point_1_ECE302_Spring2012_Boutin|Back to first bonus point opportunity, ECE302 Spring 2013]] | ||
Revision as of 11:31, 26 January 2013
If you are playing in a poker game, what is the probability of getting a royal flush, then getting four of a kind on the next hand using a 52 card deck?
If we analyze the cards in the deck, we can find that there are 52 cards in the deck. There are four suits of identical 13 cards.
To get a royal flush, you need to have an Ace, king, queen, jack and ten of the SAME suit, not different ones. so the probably is 20/52(any card between ten and ace) times 4/51 times 3/50 times 2/49 times 1/48 (4,3,2,1 are cards left in sequence, the deck also gets smaller) times 4 ( suits) which would be 6.156e-4 percent of the time.
Then to get a four of a kind, you would need 4 of any card with different suits. So you would take 1 ( any card) times 3/51 times 2/50 times 1/49. That is .0048 percent of the time.
Multiplying them together, you get 2.956e-6 percent chance of this happening. Good luck with that!
I'm a little rusty on my cards understanding, so hopefully I got the numbers in the right order.
Comments
- Congratulations on being the first one to dare posting something on this topic! -pm
- Where does the concept of conditional probability come up?
- Answer here.
- I think independence also comes up in this problem.
