(New page: Defining equation for the DFT and assume that N is even, so we have<br> <math>X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}}<\math><br><br>) |
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− | Defining equation for the DFT and assume that N is even, so we have<br> | + | Defining equation for the DFT and assume that N is even, so we have<br> |
− | + | <math>X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}}</math><br><br> |
Revision as of 17:02, 7 November 2012
Defining equation for the DFT and assume that N is even, so we have
$ X(k) = \sum_{n=0}^{N-1} x(n)e^{-j{\frac{2{\pi}kn}{N}}} $