m (ECE PhD QE CNSIP Jan 2000 Problem1.4 moved to ECE PhD QE CNSIP Jan 2001 Problem1.4: wrong year!) |
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==Question from [[ECE_PhD_QE_CNSIP_Jan_2001_Problem1|ECE QE January 2001]]== | ==Question from [[ECE_PhD_QE_CNSIP_Jan_2001_Problem1|ECE QE January 2001]]== | ||
− | + | Let <math class="inline">\mathbf{X}_{t}</math> be a band-limited white noise strictly stationary random process with bandwidth 10 KHz. It is also known that <math class="inline">\mathbf{X}_{t}</math> is uniformly distributed between <math class="inline">\pm5</math> volts. Find: | |
+ | |||
+ | '''(a) (10 pts)''' | ||
+ | |||
+ | Let <math class="inline">\mathbf{Y}_{t}=\left(\mathbf{X}_{t}\right)^{2}</math> . Find the mean square value of <math class="inline">\mathbf{Y}_{t}</math> . | ||
+ | |||
+ | '''(b) (10 pts)''' | ||
+ | |||
+ | Let <math class="inline">\mathbf{X}_{t}</math> be the input to a linear shift-invariant system with transfer function: | ||
+ | <br> | ||
+ | <math class="inline">H\left(f\right)=\begin{cases} | ||
+ | \begin{array}{lll} | ||
+ | 1 \text{ for }\left|f\right|\leq5\text{ KHz}\\ | ||
+ | 0.5 \text{ for }5\text{ KHz}\leq\left|f\right|\leq50\text{ KHz}\\ | ||
+ | 0 \text{ elsewhere. } | ||
+ | \end{array}\end{cases}</math> | ||
+ | <br> | ||
+ | |||
+ | Find the mean and variance of the output. | ||
+ | |||
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==Share and discuss your solutions below.== | ==Share and discuss your solutions below.== | ||
---- | ---- | ||
− | =Solution 1 | + | =Solution 1 = |
Write it here | Write it here | ||
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Revision as of 05:53, 17 July 2012
Contents
Question from ECE QE January 2001
Let $ \mathbf{X}_{t} $ be a band-limited white noise strictly stationary random process with bandwidth 10 KHz. It is also known that $ \mathbf{X}_{t} $ is uniformly distributed between $ \pm5 $ volts. Find:
(a) (10 pts)
Let $ \mathbf{Y}_{t}=\left(\mathbf{X}_{t}\right)^{2} $ . Find the mean square value of $ \mathbf{Y}_{t} $ .
(b) (10 pts)
Let $ \mathbf{X}_{t} $ be the input to a linear shift-invariant system with transfer function:
$ H\left(f\right)=\begin{cases} \begin{array}{lll} 1 \text{ for }\left|f\right|\leq5\text{ KHz}\\ 0.5 \text{ for }5\text{ KHz}\leq\left|f\right|\leq50\text{ KHz}\\ 0 \text{ elsewhere. } \end{array}\end{cases} $
Find the mean and variance of the output.
Solution 1
Write it here
Solution 2
Write it here.