(New page: for ( direction = 0 ; direction < 4 ; direction ) { if ( can move forward ) { go forward } // Book keeping so you know where you are } go backward /* When all four direction...) |
|||
| Line 1: | Line 1: | ||
| + | Notes for Lecture 12 - John Ribeiro | ||
| + | |||
for ( direction = 0 ; direction < 4 ; direction ) | for ( direction = 0 ; direction < 4 ; direction ) | ||
{ | { | ||
Revision as of 04:42, 21 February 2012
Notes for Lecture 12 - John Ribeiro
for ( direction = 0 ; direction < 4 ; direction ) {
if ( can move forward )
{
go forward
}
// Book keeping so you know where you are
}
go backward
/* When all four direction have led to a dead end */
Above is a sample template in order to solve ipa1-2.
- Compiler copies attribute by attribute *
Construct Frame:
c 11 b 6 a 3 value address return address
Main Frame:
v1.z = 200 + sizeof ( int ) * 2 11 v1.y = 200 + sizeof ( int ) * 1 6 v1.x = 200 3
Copy the values => *C has only pass by value / call by value
*C does not have call by reference
For ipa1-2
- Read the maze and store it in memory - Find where you can move to - Move to the place and mark your earlier location as invalid so you do no return - Keep moving until reaching the exit
Create maze structure containing the following
- Current Row/Col - Start Row/Col - Exit Row/Col - char ** maze
if ( currentRow == exitRow && exitCol = currentCol ) (
done;
}
- Structure's name NOUN w/ Capital Letter
- Function VERB w/ lower case letter
ADVANTAGES OF STRUCTURES
- Cluster related data into an "object" - Better organization and easier to understand - Easier to make changes.
* Can be changed fro new features, bug fixes, better algorithms
