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=Homework 2 collaboration area= | =Homework 2 collaboration area= | ||
| − | <math>\mathrm{ | + | <math>\mathrm{d}</math> |
<math>\sum_{n=1}^N 1 = \dfrac11N</math> | <math>\sum_{n=1}^N 1 = \dfrac11N</math> | ||
Revision as of 20:49, 3 September 2011
Homework 2 collaboration area
$ \mathrm{d} $
$ \sum_{n=1}^N 1 = \dfrac11N $
$ \sum_{n=1}^N n = \dfrac12N\left(N+1\right) $
$ \sum_{n=1}^N n\left(n+1\right) = \dfrac13N\left(N+1\right)\left(N+2\right) $
$ \vdots $ $ \vdots $
$ \sum_{n=1}^N \dfrac{\left(n+k\right)!}{\left(n-1\right)!} = \dfrac1{k+2}\cdot\dfrac{\left(N+k+1\right)!}{\left(N-1\right)!} $
