| (4 intermediate revisions by the same user not shown) | |||
| Line 1: | Line 1: | ||
| + | = Homework chapter 1&2 MA351 Spring 2011 = | ||
| − | = | + | = '''This is for some of the problem that I found hard to solve. For reviewing the final, this might help.''' = |
| + | = <br> 1.1 I find all the problem of 1.1 are very basic... no difficulty at all = | ||
| + | = <br> 1.1 3 This kind of matrix have no solution. We can just simplify it and this may improve the speed of solving problem = | ||
| − | + | = <br> = | |
| − | + | ||
| + | = 1.2 21 Four, For this kind of problem, you need to count in order. = | ||
| − | 1. | + | = 1.3 9 The form of matrix multiplication.Worth to review = |
| + | = 1.4 46 = | ||
| + | = Since a; d, and f are all nonzero, we divide the rest row by a, the second row by d, and the third row by f to obtain. = | ||
| − | 1. | + | = <br> 2.1 48. Let x be some vector in R2: Since v1 and v2 are not parallel, we can write x in terms of components of v1 and v2. So, let c1 and c2 be scalars such that x = c1v1 + c2v2 Then, by Fact 2.1.3 ,we can solve the problem = |
| − | + | = 2.2 27. I guess the best way to solve this kind of problem is remember the form of projection, shear, and refection. = | |
| − | + | = <br> = | |
| − | + | = 2.3 43-48, Steps :1. Guess what kind of transformation 2 solve. I am very bad at this type of problems.BTW there’s one of the exam 1 as well = | |
| − | + | ||
| − | 2. | + | = <br> 2.4 Inverse, this section is not on the hw but on the exam. = |
| − | + | ||
| − | + | ||
| − | + | = Just keep in mind that there are 4 condition brought up by this section that are equal to each other.<br> = | |
| − | + | <br> | |
| + | <br> | ||
| − | + | <br> | |
| − | + | ||
| + | '''<br> By Bingrou Zhou''' | ||
| + | <br> | ||
| − | + | [[2011 Spring MA 35100 Kummini|Back to 2011 Spring MA 35100 Kummini]] | |
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | + | ||
| − | [[ 2011 Spring MA 35100 Kummini|Back to 2011 Spring MA 35100 Kummini]] | + | |
Latest revision as of 14:50, 30 April 2011
Contents
- 1 Homework chapter 1&2 MA351 Spring 2011
- 2 This is for some of the problem that I found hard to solve. For reviewing the final, this might help.
- 3 1.1 I find all the problem of 1.1 are very basic... no difficulty at all
- 4 1.1 3 This kind of matrix have no solution. We can just simplify it and this may improve the speed of solving problem
- 5
- 6 1.2 21 Four, For this kind of problem, you need to count in order.
- 7 1.3 9 The form of matrix multiplication.Worth to review
- 8 1.4 46
- 9 Since a; d, and f are all nonzero, we divide the rest row by a, the second row by d, and the third row by f to obtain.
- 10 2.1 48. Let x be some vector in R2: Since v1 and v2 are not parallel, we can write x in terms of components of v1 and v2. So, let c1 and c2 be scalars such that x = c1v1 + c2v2 Then, by Fact 2.1.3 ,we can solve the problem
- 11 2.2 27. I guess the best way to solve this kind of problem is remember the form of projection, shear, and refection.
- 12
- 13 2.3 43-48, Steps :1. Guess what kind of transformation 2 solve. I am very bad at this type of problems.BTW there’s one of the exam 1 as well
- 14 2.4 Inverse, this section is not on the hw but on the exam.
- 15 Just keep in mind that there are 4 condition brought up by this section that are equal to each other.
Homework chapter 1&2 MA351 Spring 2011
This is for some of the problem that I found hard to solve. For reviewing the final, this might help.
1.1 I find all the problem of 1.1 are very basic... no difficulty at all
1.1 3 This kind of matrix have no solution. We can just simplify it and this may improve the speed of solving problem
1.2 21 Four, For this kind of problem, you need to count in order.
1.3 9 The form of matrix multiplication.Worth to review
1.4 46
Since a; d, and f are all nonzero, we divide the rest row by a, the second row by d, and the third row by f to obtain.
2.1 48. Let x be some vector in R2: Since v1 and v2 are not parallel, we can write x in terms of components of v1 and v2. So, let c1 and c2 be scalars such that x = c1v1 + c2v2 Then, by Fact 2.1.3 ,we can solve the problem
2.2 27. I guess the best way to solve this kind of problem is remember the form of projection, shear, and refection.
2.3 43-48, Steps :1. Guess what kind of transformation 2 solve. I am very bad at this type of problems.BTW there’s one of the exam 1 as well
2.4 Inverse, this section is not on the hw but on the exam.
Just keep in mind that there are 4 condition brought up by this section that are equal to each other.
By Bingrou Zhou
