(New page: For question 1, is omega_c > 0 the same as "there are no conditions set"?) |
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For question 1, is omega_c > 0 the same as "there are no conditions set"? | For question 1, is omega_c > 0 the same as "there are no conditions set"? | ||
+ | :no, because it excludes <math>\omega_c=0</math>. The carrier frequency <math>\omega_c=0</math> could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm | ||
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+ | For question 1b), should <math class="inline">e^{-j(\omega_c+\theta_c)}</math> be <math class="inline">e^{-j(\omega_ct+\theta_c)}</math> ? | ||
+ | :Yes, you are right. The correction has been made. -pm | ||
+ | ---- |
Latest revision as of 09:04, 19 April 2011
For question 1, is omega_c > 0 the same as "there are no conditions set"?
- no, because it excludes $ \omega_c=0 $. The carrier frequency $ \omega_c=0 $ could be equal to zero, in which case, the signal would simply be multiplied by one. Of course, one can then recover the signal! -pm
For question 1b), should $ e^{-j(\omega_c+\theta_c)} $ be $ e^{-j(\omega_ct+\theta_c)} $ ?
- Yes, you are right. The correction has been made. -pm