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[[Category: asan]]
 
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[[Category: Bonus]]
 
[[Category: Bonus]]
Given:
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=Proof of the Commutativity property of LTI systems ([[ECE301]])=
 
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Given: <math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
<math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
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#<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
 
#<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math>
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#<math> x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k'])</math> from 1 and 2
 
#<math> x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k'])</math> from 1 and 2
 
#<math> x[n]*h[n]=h[n]*x[n]</math>
 
#<math> x[n]*h[n]=h[n]*x[n]</math>
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Latest revision as of 10:27, 30 January 2011

Proof of the Commutativity property of LTI systems (ECE301)

Given: $ y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $

  1. $ x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
  2. $ k'=n-k $
  3. $ x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k']) $ from 1 and 2
  4. $ x[n]*h[n]=h[n]*x[n] $

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