(New page: Category:ECE301Spring2011Boutin Category:problem solving = Compute the Magnitude of the following continuous-time signals= a) <math>x(t)=e^{2t}</math> b) <math>x(t)=e^{2jt}</math>...) |
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===Answer 1=== | ===Answer 1=== | ||
| − | + | a) <math class="inline">|e^{(2t)}| = \sqrt{(e^{(2t)})^2} = \sqrt{e^{(4t)}} = e^{(2t)}</math> ([[User:cmcmican|cmcmican]] 10:59, 10 January 2011 (UTC)) | |
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| + | b) <math class="inline">|e^{(2jt)}| = |(cos(2t) + j*sin(2t))| = \sqrt{(cos(2t))^2 + (sin(2t))^2} = \sqrt{1} = 1</math> ([[User:cmcmican|cmcmican]] 10:59, 10 January 2011 (UTC)) | ||
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===Answer 2=== | ===Answer 2=== | ||
write it here. | write it here. | ||
Revision as of 17:56, 10 January 2011
Contents
Compute the Magnitude of the following continuous-time signals
a) $ x(t)=e^{2t} $
b) $ x(t)=e^{2jt} $
What properties of the complex magnitude can you use to check your answer?
You will receive feedback from your instructor and TA directly on this page. Other students are welcome to comment/discuss/point out mistakes/ask questions too!
Answer 1
a) $ |e^{(2t)}| = \sqrt{(e^{(2t)})^2} = \sqrt{e^{(4t)}} = e^{(2t)} $ (cmcmican 10:59, 10 January 2011 (UTC))
b) $ |e^{(2jt)}| = |(cos(2t) + j*sin(2t))| = \sqrt{(cos(2t))^2 + (sin(2t))^2} = \sqrt{1} = 1 $ (cmcmican 10:59, 10 January 2011 (UTC))
Answer 2
write it here.
Answer 3
write it here.
