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You'll get an ugly integral evaluation but most terms cancel and it leaves you with 3 sine terms that then go into the fourier series. | You'll get an ugly integral evaluation but most terms cancel and it leaves you with 3 sine terms that then go into the fourier series. | ||
| − | |||
Question, Page 547, Problem 15: | Question, Page 547, Problem 15: | ||
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How do we show p_n? I think I understand that this is part of calculating lambdas using the Sturm-Louiville, but I haven't been able to figure it out. | How do we show p_n? I think I understand that this is part of calculating lambdas using the Sturm-Louiville, but I haven't been able to figure it out. | ||
| − | Answer: The p_n come from the boundary conditions. The problem is similar | + | Answer: The p_n come from the boundary conditions. (The problem is similar |
| − | to the Sturm-Liouville problem on Exam 2. | + | to the Sturm-Liouville problem on Exam 2.) The boundary conitions are |
| + | X(0)=0 and X'(L)=0. | ||
Question, Page 548, Problem 16: | Question, Page 548, Problem 16: | ||
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Answer: There is no f(x) in this problem. (You can see that initial conditions | Answer: There is no f(x) in this problem. (You can see that initial conditions | ||
| − | are set in the next problem, which is a continuation of the whole thing. | + | are set in the next problem, which is a continuation of the whole thing.) |
[[2010 MA 527 Bell|Back to the MA 527 start page]] | [[2010 MA 527 Bell|Back to the MA 527 start page]] | ||
Revision as of 05:59, 28 November 2010
Homework 13 collaboration area
Question, Page 546, Problem 9:
Are the Boundary Conditions u(1/4,t) = 0 and u(3/4,t)=0 or u(0,t)=1/4 and u(L,t)=3/4? Also, can anyone help explain what f(x) is in this problem? I think g(x) = 0, but I'm not sure about f(x)?
Answer: Boundary Conditions: u(0,t) = 0, u(L,t) = 0. In this problem, L=1.
Initial Conditions: u(x,0)= f(x), which can be seen from the diagram as
f(x) = x - 1/4 for 1/4 < x < 1/2 and f(x) = -x + 3/4 for 1/2 < x < 3/4.
(Actually, the initial shape is supposed to be k=.01 times this, but that just puts the same k in front of the series for the solution.)
You'll have to split up the integral when calculating A_n. And yes, the last Initial Condition is
d(u)/dt(x,0) = g(x) = 0.
You'll get an ugly integral evaluation but most terms cancel and it leaves you with 3 sine terms that then go into the fourier series.
Question, Page 547, Problem 15:
How do we show that the constant is beta^4 without any boundary conditions to work with?
Answer. The beta to the fourth power is just a way to name the positive constant lambda to make the solutions easier to write. There will also be the cases lambda=0 and lambda negative (= minus beta to the fourth) to deal with. You won't use boundary conditions to eliminate solutions until problem 16.
Question, Page 552, Problem 5:
How do we show p_n? I think I understand that this is part of calculating lambdas using the Sturm-Louiville, but I haven't been able to figure it out.
Answer: The p_n come from the boundary conditions. (The problem is similar to the Sturm-Liouville problem on Exam 2.) The boundary conitions are
X(0)=0 and X'(L)=0.
Question, Page 548, Problem 16:
What about f(x) for this problem? I am really having a hard time identifying the f(x) for these problems. (Actually, this entire section in general) Does anybody know of a good reference for example problems?
Answer: There is no f(x) in this problem. (You can see that initial conditions are set in the next problem, which is a continuation of the whole thing.)
