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Let A and B be n × n matrices.
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Let ''A'' and ''B'' be ''n × n'' matrices and ''I''<sub>''n''</sub> be the ''n × n'' identity matrix
  
 
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   0 & 0 & \cdots  & 1  \\
 
   0 & 0 & \cdots  & 1  \\
 
\end{matrix} \right)}^{{{I}_{n}}} \\  
 
\end{matrix} \right)}^{{{I}_{n}}} \\  
\end{align}</math>
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\end{align}</math>  
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[[Category:MA265Fall2010Walther]]
 
[[Category:MA265Fall2010Walther]]

Revision as of 14:24, 27 November 2010

The Inverse of a Matrix

In linear algebra, the study of matrices is one of the fundamental basis of this subject. One of the concepts within this study, is the notion of an invertible or nonsingular matrix.


Definition

A square matrix is said to be invertible or nonsingular, if when multiplied by another similar matrix, the result yields the identity matrix.


Let A and B be n × n matrices and In be the n × n identity matrix


A is invertible or nonsingular and B is its inverse if:


$ \begin{align} & AB=BA={{I}_{n}} \\ & \\ & \overbrace{\left( \begin{matrix} {{a}_{11}} & {{a}_{12}} & \cdots & {{a}_{1n}} \\ {{a}_{21}} & {{a}_{22}} & \cdots & {{a}_{2n}} \\ \vdots & \vdots & \ddots & \vdots \\ {{a}_{n1}} & {{a}_{n2}} & \cdots & {{a}_{nn}} \\ \end{matrix} \right)}^{A}\overbrace{\left( \begin{matrix} {{b}_{11}} & {{b}_{12}} & \cdots & {{b}_{1n}} \\ {{b}_{21}} & {{b}_{22}} & \cdots & {{b}_{2n}} \\ \vdots & \vdots & \ddots & \vdots \\ {{b}_{n1}} & {{b}_{n2}} & \cdots & {{b}_{nn}} \\ \end{matrix} \right)}^{B}=\overbrace{\left( \begin{matrix} 1 & 0 & \cdots & 0 \\ 0 & 1 & \cdots & 0 \\ \vdots & \vdots & \ddots & \vdots \\ 0 & 0 & \cdots & 1 \\ \end{matrix} \right)}^{{{I}_{n}}} \\ \end{align} $

Alumni Liaison

Questions/answers with a recent ECE grad

Ryne Rayburn