| Line 2: | Line 2: | ||
which are | which are | ||
B1 B2 B3 | B1 B2 B3 | ||
| + | |||
[5 0 0] | [5 0 0] | ||
[4 1 0] | [4 1 0] | ||
Revision as of 14:29, 28 September 2008
The total number of ways could be found by innumerating all the possible cases, which are B1 B2 B3
[5 0 0] [4 1 0] [3 2 0] [3 1 1] [2 2 1]
Hence 5 is the answer.
