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==Homework 5 Discussion== | ==Homework 5 Discussion== | ||
Please post your questions or comments here | Please post your questions or comments here | ||
− | + | ---- | |
− | + | ==How to solve question 2?== | |
− | + | ||
Anyone have any guidance on this? Thanks --[[User:Haddada|Haddada]] 20:46, 21 October 2010 (UTC) | Anyone have any guidance on this? Thanks --[[User:Haddada|Haddada]] 20:46, 21 October 2010 (UTC) | ||
+ | *It would help if you wrote the question: somebody not in the class might be able to pitch in. -pm | ||
+ | *Here is part of my solution. For question a, suppose N is the rv. that equals to the number of balls you need and p is the prob. that a ball is put into ith bag | ||
− | + | ::Then p=1/n | |
− | + | ::<math>P(N=k)=(1-p)^kp=(1-\frac{1}{n})^k\frac{1}{n}</math> | |
− | + | ::<math> | |
− | + | ||
− | <math> | + | |
\begin{align} | \begin{align} | ||
E[N]=\sum_{k=0}^{\infty}kP(N=k)&=\sum_{k=0}^{\infty}k(1-\frac{1}{n})^k\frac{1}{n} \\ | E[N]=\sum_{k=0}^{\infty}kP(N=k)&=\sum_{k=0}^{\infty}k(1-\frac{1}{n})^k\frac{1}{n} \\ | ||
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\end{align} | \end{align} | ||
</math> | </math> | ||
− | + | :For question b, I was stucked. | |
− | For question b, I was stucked. | + | :--[[User:zhao148|Zhao]] 23:50, 21 October 2010 (UTC) |
− | + | ||
− | --[[User:zhao148|Zhao]] 23:50, 21 October 2010 (UTC) | + | |
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Latest revision as of 10:58, 22 October 2010
Homework 5 Discussion
Please post your questions or comments here
How to solve question 2?
Anyone have any guidance on this? Thanks --Haddada 20:46, 21 October 2010 (UTC)
- It would help if you wrote the question: somebody not in the class might be able to pitch in. -pm
- Here is part of my solution. For question a, suppose N is the rv. that equals to the number of balls you need and p is the prob. that a ball is put into ith bag
- Then p=1/n
- $ P(N=k)=(1-p)^kp=(1-\frac{1}{n})^k\frac{1}{n} $
- $ \begin{align} E[N]=\sum_{k=0}^{\infty}kP(N=k)&=\sum_{k=0}^{\infty}k(1-\frac{1}{n})^k\frac{1}{n} \\ &=(1-\frac{1}{n})\frac{1}{n}+2(1-\frac{1}{n})^2\frac{1}{n}+3(1-\frac{1}{n})^3\frac{1}{n}+... \\ &=(1-\frac{1}{n})\frac{1}{n}+(1-\frac{1}{n})^2\frac{1}{n}+(1-\frac{1}{n})^3\frac{1}{n}+... \\ &+(1-\frac{1}{n})^2\frac{1}{n}+(1-\frac{1}{n})^3\frac{1}{n}+... \\ &+(1-\frac{1}{n})^3\frac{1}{n}+... \\ &=(1-\frac{1}{n})+(1-\frac{1}{n})^2+(1-\frac{1}{n})^3+... \\ &=n-1 \end{align} $
- For question b, I was stucked.
- --Zhao 23:50, 21 October 2010 (UTC)