(New page: I made three colums, all labeled "Box" to signify the three indistinguishable boxes. Writing out the combinations I found there could be: 5 in one 4 in one and 1 in another 3 in one, 1 i...)
 
 
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I made three colums, all labeled "Box" to signify the three indistinguishable boxes.
 
I made three colums, all labeled "Box" to signify the three indistinguishable boxes.
Writing out the combinations I found there could be:
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Writing out the combinations I found there could be
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5 in one
 
5 in one
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4 in one and 1 in another
 
4 in one and 1 in another
 +
 
3 in one, 1 in another, and 1 in the last
 
3 in one, 1 in another, and 1 in the last
 +
 
3 in one and 3 in another
 
3 in one and 3 in another
 +
 
2 in one, 1 in another, and 2 in the last
 
2 in one, 1 in another, and 2 in the last
 +
  
 
for a total of five solutions.
 
for a total of five solutions.
  
 
--[[User:Tmsteinh|Tmsteinh]] 17:51, 24 September 2008 (UTC)
 
--[[User:Tmsteinh|Tmsteinh]] 17:51, 24 September 2008 (UTC)
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Great job! This method/solution looks perfect to me :)
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--[[User:Zhao14|Zhao14]] 08:11, 3 October 2008 (UTC)

Latest revision as of 03:11, 3 October 2008

I made three colums, all labeled "Box" to signify the three indistinguishable boxes. Writing out the combinations I found there could be


5 in one

4 in one and 1 in another

3 in one, 1 in another, and 1 in the last

3 in one and 3 in another

2 in one, 1 in another, and 2 in the last


for a total of five solutions.

--Tmsteinh 17:51, 24 September 2008 (UTC)



Great job! This method/solution looks perfect to me :) --Zhao14 08:11, 3 October 2008 (UTC)

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