Line 7: | Line 7: | ||
According to the Sampling Theorem, sample rate <math>f_s>=2f</math> | According to the Sampling Theorem, sample rate <math>f_s>=2f</math> | ||
− | So the maximum T is <math>\frac{ | + | So the maximum T is <math>\frac{\pi}{\omega}</math>. |
------------------------------------- | ------------------------------------- | ||
[[ECE438_Week6_Quiz|Back to Pool]] | [[ECE438_Week6_Quiz|Back to Pool]] |
Revision as of 11:16, 29 September 2010
Quiz Pool Question1 Solution:
Recall: $ \omega =2\pi f $
The highest frequency of the continuous signal is $ f=\frac{\omega}{2\pi} $
According to the Sampling Theorem, sample rate $ f_s>=2f $
So the maximum T is $ \frac{\pi}{\omega} $.