(New page: Recall: <math>\omega =2\pi f</math> The highest frequency of the continuous signal is <math>f=\frac{\omega}{2\pi}</math> According to the Sampling Theorem, sample rate <math>f_s>=2f</mat...) |
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Recall: <math>\omega =2\pi f</math> | Recall: <math>\omega =2\pi f</math> | ||
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So the maximum T is <math>\frac{4\pi}{\omega}</math>. | So the maximum T is <math>\frac{4\pi}{\omega}</math>. | ||
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Revision as of 15:50, 26 September 2010
Quiz Pool Question1 Solution:
Recall: $ \omega =2\pi f $
The highest frequency of the continuous signal is $ f=\frac{\omega}{2\pi} $
According to the Sampling Theorem, sample rate $ f_s>=2f $
So the maximum T is $ \frac{4\pi}{\omega} $.
