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| − | Would part A just be C(12,7)? Where 12 is how many croissants you can choose from and 7 is how many types of croissants there are to choose from? | + | *Would part A just be C(12,7)? Where 12 is how many croissants you can choose from and 7 is how many types of croissants there are to choose from? |
| − | Wouldn't it be C(12,6) with repetition since there's 6 different type of croissants and after you choose one you can choose it again if you want to. | + | **Wouldn't it be C(12,6) with repetition since there's 6 different type of croissants and after you choose one you can choose it again if you want to. |
| − | Yeah nevermind, I mean't C(12,6). | + | **Yeah nevermind, I mean't C(12,6). |
| − | For part C, how could you compensate for counting "at least 2 of each croissant"? | + | *For part C, how could you compensate for counting "at least 2 of each croissant"? |
| − | For part C and the following problems, I had a+b+c+d+e+f=24 and we know that a>=2 so then we have a'=a-2... So with the following we have (a'+2)+(b'+2)+(c'+2)...+(f'+2)=24. So then subtracting all of the 2s, we have a'+b'+c'+d'+e'+f'=12. So then we have C(12+6-1,6)= C(17,6)=12,376 | + | **For part C and the following problems, I had a+b+c+d+e+f=24 and we know that a>=2 so then we have a'=a-2... So with the following we have (a'+2)+(b'+2)+(c'+2)...+(f'+2)=24. So then subtracting all of the 2s, we have a'+b'+c'+d'+e'+f'=12. So then we have C(12+6-1,6)= C(17,6)=12,376 |
| − | Isn't this entire problem about the bars and stars? You have 6 types, 12 to choose. Use 5 bars and 12 stars: |***|***|**|**|** for A. So, the answer is (12 + 6 - 1) choose 5. And for C, you basically just select 2*6 from the stacks first. This leaves you with 12 more to select. So the answer to C is the answer to A. | + | *Isn't this entire problem about the bars and stars? You have 6 types, 12 to choose. Use 5 bars and 12 stars: |***|***|**|**|** for A. So, the answer is (12 + 6 - 1) choose 5. And for C, you basically just select 2*6 from the stacks first. This leaves you with 12 more to select. So the answer to C is the answer to A. |
| − | *Yea stars and bars!!!--[[User:Aifrank|Aifrank]] 18:22, 23 September 2008 (UTC) | + | **Yea stars and bars!!!--[[User:Aifrank|Aifrank]] 18:22, 23 September 2008 (UTC) |
| − | I thought it was about the croissants! Am I in the wrong section? | + | **I thought it was about the croissants! Am I in the wrong section? |
| − | I hope this helps, I don't know anything about technology, but I posted on this and wanted to have the link come up... hope it works this time!! | + | *I hope this helps, I don't know anything about technology, but I posted on this and wanted to have the link come up... hope it works this time!! |
Revision as of 13:25, 23 September 2008
- Would part A just be C(12,7)? Where 12 is how many croissants you can choose from and 7 is how many types of croissants there are to choose from?
- Wouldn't it be C(12,6) with repetition since there's 6 different type of croissants and after you choose one you can choose it again if you want to.
- Yeah nevermind, I mean't C(12,6).
- For part C, how could you compensate for counting "at least 2 of each croissant"?
- For part C and the following problems, I had a+b+c+d+e+f=24 and we know that a>=2 so then we have a'=a-2... So with the following we have (a'+2)+(b'+2)+(c'+2)...+(f'+2)=24. So then subtracting all of the 2s, we have a'+b'+c'+d'+e'+f'=12. So then we have C(12+6-1,6)= C(17,6)=12,376
- Isn't this entire problem about the bars and stars? You have 6 types, 12 to choose. Use 5 bars and 12 stars: |***|***|**|**|** for A. So, the answer is (12 + 6 - 1) choose 5. And for C, you basically just select 2*6 from the stacks first. This leaves you with 12 more to select. So the answer to C is the answer to A.
- Yea stars and bars!!!--Aifrank 18:22, 23 September 2008 (UTC)
- I thought it was about the croissants! Am I in the wrong section?
- I hope this helps, I don't know anything about technology, but I posted on this and wanted to have the link come up... hope it works this time!!
