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| − | Then, <math>f(E) = {f(x) : 1 \ | + | Then, <math>f(E) = {f(x) : 1 \le x \le 2}</math> |
| − | <math> 1/4 \ | + | <math> 1/4 \le f(E) \le 1</math> |
Then, <math>f(E) = {y : 1/4 <= y <= 1}</math> | Then, <math>f(E) = {y : 1/4 <= y <= 1}</math> | ||
Revision as of 12:39, 7 February 2010
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I am having trouble with question 8 from our first HW. I am going back and trying to fix my old HW. I got back my HW and got a 0 out of 25. Can any one help get me started?
Thanks,
Andrew
8.(a)
$ f(1) = 1 / 1^2 = 1 / 1 = 1 $
$ f(2) = 1 / 2^2 = 1/4 $
Then, $ f(E) = {f(x) : 1 \le x \le 2} $
$ 1/4 \le f(E) \le 1 $
Then, $ f(E) = {y : 1/4 <= y <= 1} $
