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[http://www.math.purdue.edu/~bell/MA425/hwk7.txt HWK 7 problems] | [http://www.math.purdue.edu/~bell/MA425/hwk7.txt HWK 7 problems] | ||
| − | For VII.4.1 I get the bottom side of the rectangle tends to pi and the sides tend to 0. But when I try and evaluate the top side by letting <math>z (t) = 2at - a + \sqrt b i</math>, my integrand becomes a mess: <math>2a/((4a^2 t^2-4a^2 t+a^2-b+1)+i(4a\sqrt b t-2a\sqrt b))</math>. I don't see how that simplifies to what the integrand in the problem gives. Just keep messing around with the algebra until something happens? Or did I do something wrong--[[User:Aata|Aata]] | + | For VII.4.1 I get the bottom side of the rectangle tends to pi and the sides tend to 0. But when I try and evaluate the top side by letting <math>z (t) = 2at - a + \sqrt b i</math>, my integrand becomes a mess: <math>2a/((4a^2 t^2-4a^2 t+a^2-b+1)+i(4a\sqrt b t-2a\sqrt b))</math>. I don't see how that simplifies to what the integrand in the problem gives. Just keep messing around with the algebra until something happens? Or did I do something wrong |
| + | Edit: Never mind, I figured it out by changing the parametrization so <math>-a<=t<=a</math>--[[User:Aata|Aata]] | ||
Revision as of 14:56, 29 October 2009
Homework 7
For VII.4.1 I get the bottom side of the rectangle tends to pi and the sides tend to 0. But when I try and evaluate the top side by letting $ z (t) = 2at - a + \sqrt b i $, my integrand becomes a mess: $ 2a/((4a^2 t^2-4a^2 t+a^2-b+1)+i(4a\sqrt b t-2a\sqrt b)) $. I don't see how that simplifies to what the integrand in the problem gives. Just keep messing around with the algebra until something happens? Or did I do something wrong Edit: Never mind, I figured it out by changing the parametrization so $ -a<=t<=a $--Aata
