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− | + | It would be amazing if someone could explain the intersection between A and B on problem number 12. I have so far the squares being 31 and the cubes being 10. But I am not sure how to get the intersection. Any ideas? Also I do not understand 20 or 28 at all. If someone could please help me out that would ROCK! Thanks | |
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− | + | === Possible Solutions === | |
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I think that if you want numbers between 1 and 1,000 that are both cubes and squares you'd do (1,000)^1/6 | I think that if you want numbers between 1 and 1,000 that are both cubes and squares you'd do (1,000)^1/6 | ||
but thats just my guess because when you want, | but thats just my guess because when you want, | ||
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31+10-3=38 | 31+10-3=38 | ||
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+ | == #28 in 7.5 == | ||
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+ | Can someone rephrase the question or shed some light on what this question is asking? I looked at the solution for #29 which seems to be quite similar, but it was a notation we haven't learned in class. |
Revision as of 14:20, 3 September 2008
#12 in 7.5
It would be amazing if someone could explain the intersection between A and B on problem number 12. I have so far the squares being 31 and the cubes being 10. But I am not sure how to get the intersection. Any ideas? Also I do not understand 20 or 28 at all. If someone could please help me out that would ROCK! Thanks
Possible Solutions
I think that if you want numbers between 1 and 1,000 that are both cubes and squares you'd do (1,000)^1/6 but thats just my guess because when you want,
how many squares: (1,000)^1/2 = 31
how many cubics: (1,000)^1/3= 10
so how many squares and cubics: (1,000)^1/6 = 3
12. A: # of squares: 31 B: # of cubics: 10 A intersection B: 3
31+10-3=38
#28 in 7.5
Can someone rephrase the question or shed some light on what this question is asking? I looked at the solution for #29 which seems to be quite similar, but it was a notation we haven't learned in class.