Line 5: | Line 5: | ||
[[Category: asan]] | [[Category: asan]] | ||
[[Category: Bonus]] | [[Category: Bonus]] | ||
− | Given: | + | Given: <math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math> |
− | + | ||
− | <math>y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math> | + | |
#<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math> | #<math> x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k])</math> |
Revision as of 06:40, 25 November 2008
Given: $ y[n]=x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
- $ x[n]*h[n]=\sum_{k=-\infty}^{\infty}(x[k]h[n-k]) $
- $ k'=n-k $
- $ x[n]*h[n]=\sum_{k'=\infty}^{-\infty}(x[n-k']h[k']) $ from 1 and 2
- $ x[n]*h[n]=h[n]*x[n] $