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<math>(1/T)*\int|x(t)|^2 = \sum|ak|^2</math>
 
<math>(1/T)*\int|x(t)|^2 = \sum|ak|^2</math>
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The integral is taken over the interval of T.  The sum is taken from -infinity to infinity.

Latest revision as of 15:54, 27 July 2009

$ (1/T)*\int|x(t)|^2 = \sum|ak|^2 $

The integral is taken over the interval of T. The sum is taken from -infinity to infinity.

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