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<math>x(t)=\cos(t)+j*\sin(t)</math> | <math>x(t)=\cos(t)+j*\sin(t)</math> | ||
− | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{- | + | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T |x(t)|^2dt</math> |
− | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{- | + | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T |\cos(t)+j\sin(t)|^2dt</math> |
− | <math>P\infty=\lim_{T \to \infty}\int_{- | + | <math>P\infty=\lim_{T \to \infty}\int_{-T}^T|e^{j*t}|^2dt</math> |
− | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{- | + | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T|e^2*e^{j*t}|dt</math> |
− | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{- | + | <math>P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T|e^2*e^{j*t}|dt</math> |
− | <math>P\infty=\frac{\int_{-\infty}^\infty |e^2*e^{j*t}|dt}{\lim_{T \to \infty}2*T*\int_{- | + | <math>P\infty=\frac{\int_{-\infty}^\infty |e^2*e^{j*t}|dt}{\lim_{T \to \infty}2*T*\int_{-T}^T|e^2*e^{j*t}|dt)}</math> |
<math>P\infty=\frac{1}{\lim_{T \to \infty}2*T}</math> | <math>P\infty=\frac{1}{\lim_{T \to \infty}2*T}</math> | ||
− | |||
<math>P\infty=0</math> | <math>P\infty=0</math> |
Revision as of 19:35, 20 June 2009
Compute $ E\infty $
$ x(t)=\cos(t)+j*\sin(t) $
$ E\infty=\int_{-\infty}^\infty |x(t)|^2dt $
$ E\infty=\int_{-\infty}^\infty |\cos(t)+j\sin(t)|^2dt $
$ E\infty=\int_{-\infty}^\infty |e^{j*t}|^2dt $
$ E\infty=\int_{-\infty}^\infty |e^2*e^{j*t}|dt $
$ E\infty=e^2/j*(\infty-0) $
$ E\infty=\infty $
Compute $ P\infty $
$ x(t)=\cos(t)+j*\sin(t) $
$ P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T |x(t)|^2dt $
$ P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T |\cos(t)+j\sin(t)|^2dt $
$ P\infty=\lim_{T \to \infty}\int_{-T}^T|e^{j*t}|^2dt $
$ P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T|e^2*e^{j*t}|dt $
$ P\infty=\lim_{T \to \infty}\frac{1}{2*T}\int_{-T}^T|e^2*e^{j*t}|dt $
$ P\infty=\frac{\int_{-\infty}^\infty |e^2*e^{j*t}|dt}{\lim_{T \to \infty}2*T*\int_{-T}^T|e^2*e^{j*t}|dt)} $
$ P\infty=\frac{1}{\lim_{T \to \infty}2*T} $
$ P\infty=0 $