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The solution is very simple, and doesn't require that you use series, just some inductive logic and limits.--[[User:Jmason|John Mason]] 16:58, 17 October 2008 (UTC) | The solution is very simple, and doesn't require that you use series, just some inductive logic and limits.--[[User:Jmason|John Mason]] 16:58, 17 October 2008 (UTC) | ||
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| + | If you had 8 teams: | ||
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| + | *All 8 play at least 1 game. | ||
| + | *4 winners of the 1st games play two games. | ||
| + | *2 winners of the 2nd games play again for a third time. | ||
| + | *Average would be <math> \frac{(8*4 + 2*2 + 2*3)}{8} </math> | ||
Revision as of 16:47, 18 October 2008
The solution is very simple, and doesn't require that you use series, just some inductive logic and limits.--John Mason 16:58, 17 October 2008 (UTC)
If you had 8 teams:
- All 8 play at least 1 game.
- 4 winners of the 1st games play two games.
- 2 winners of the 2nd games play again for a third time.
- Average would be $ \frac{(8*4 + 2*2 + 2*3)}{8} $
