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| − | Therefore, <math> m_k = \left ( \frac {1}{k\pi} \sin ( \frac {k\pi}{4} ) ) </math> | + | Therefore, <math> m_k = \left ( \frac {1}{k\pi} \sin ( \frac {k\pi}{4} ) \right) </math> |
Revision as of 11:03, 1 July 2008
Let $ g(t) = \left ( \frac{dz}{dt} \right ) $
Therefore, $ m_k = \left ( \frac {1}{k\pi} \sin ( \frac {k\pi}{4} ) \right) $
