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it is the right riemann is the eror is the last one
  
 
==[[Learn LaTeX_MA181Fall2008bell]]==
 
==[[Learn LaTeX_MA181Fall2008bell]]==

Revision as of 05:40, 17 September 2008

Math 181 Honors Calculus

Getting started editing

Lecture Notes

Homework Help

Hello, this is gary from ma181. let's solve the extra credit problem. Here is the problem in italics:

"Extra Credit Problem


Suppose that f(x) is continuously differentiable on the interval [a,b]. Let N be a positive integer and let M = Max { |f'(x)| : a <= x <= b }. Let h = (b-a)/N and let R_N denote the "right endpoint" Riemann Sum for the integral

I = int( f(x), x=a..b).

In other words,

R_N = sum( f(a + n*h)*h , n=1..N ).

Explain why the error, E = | R_N - I |, satisfies

E < M(b-a)^2/N."

So what does this equation "E < M(b-a)^2/N" mean. This reads that the error is less than the Maximum value of the derivative of the function of x multiplied by the interval squared from x=a to x=b all divided by the total number of subintervals N.

I don't understand why this must be true. Maybe I'm wrong, but if f(x) were a horizontal line, wouldn't E=0 and M(b-a)^2/N also be =0. That would mean it is a false statement that E < M(b-a)^2/N. Are we to assume that E <= M(b-a)^2/N?

Interesting Articles about Calculus

The minimum volume happens at the average_MA181Fall2008bell


it is the right riemann is the eror is the last one

Learn LaTeX_MA181Fall2008bell

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin