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<math> \theta = \pi </math>
 
<math> \theta = \pi </math>
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C) <math> (1 + j)^{5} </math>
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<math> r = \sqrt{1^2 + 1^2} = \sqrt{2} </math>
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<math> \theta = \frac{\pi}{4} </math>
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<math> (1 + j) = \sqrt{2}e^{j\frac{\pi}{4}} </math>
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<math> (1 + j)^5 = \sqrt{2}e^{j\frac{\pi}{4}}^5 = 2^{\frac{5}{2}}e^{j\frac{5\pi}{4}} </math>

Revision as of 00:16, 13 June 2008

Express each of the following complex numbers in polar form, and plot them in the complex plane, indicating the magnitude and angle of each number.

A) $ 1 + j\sqrt{3} $

$ r = \sqrt{1^2 + \sqrt{3}^2} = \sqrt{4} = 2 $

$ \theta = arctan(\sqrt{3}/1) = arctan(\sqrt{3}) = \frac{\pi}{3} $

Therefore the polar form of this complex number is: $ 2e^{j\frac{\pi}{3}} $

B) $ -5 $

$ r = 5 $

$ \theta = \pi $

C) $ (1 + j)^{5} $

$ r = \sqrt{1^2 + 1^2} = \sqrt{2} $

$ \theta = \frac{\pi}{4} $

$ (1 + j) = \sqrt{2}e^{j\frac{\pi}{4}} $

$ (1 + j)^5 = \sqrt{2}e^{j\frac{\pi}{4}}^5 = 2^{\frac{5}{2}}e^{j\frac{5\pi}{4}} $

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Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett