(New page: I wasn't entirely sure about this problem, but I think the general idea is that the multiplicative set of F of nonzero elements forms a group under multiplication. Since it has n-1 elemen...)
 
 
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I wasn't entirely sure about this problem, but I think the general idea is that the multiplicative set of F of nonzero elements forms a group under multiplication.  Since it has n-1 elements then, by property of groups, x^(n-1) =1 for all nonzero x in F.<br>
 
I wasn't entirely sure about this problem, but I think the general idea is that the multiplicative set of F of nonzero elements forms a group under multiplication.  Since it has n-1 elements then, by property of groups, x^(n-1) =1 for all nonzero x in F.<br>
 
--[[User:Jniederh|Jniederh]] 20:08, 25 March 2009 (UTC)
 
--[[User:Jniederh|Jniederh]] 20:08, 25 March 2009 (UTC)

Latest revision as of 15:15, 25 March 2009


I wasn't entirely sure about this problem, but I think the general idea is that the multiplicative set of F of nonzero elements forms a group under multiplication. Since it has n-1 elements then, by property of groups, x^(n-1) =1 for all nonzero x in F.
--Jniederh 20:08, 25 March 2009 (UTC)

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Questions/answers with a recent ECE grad

Ryne Rayburn