(New page: 6.1 #38 Coin tossed 3 times. Possible Outcomes: TTT HHH TTH HHT THT HTH THH HTT Are the following independent? ie. p(A intersection B) = p(A)* p(B) a. First coin tails Secon...)
 
Line 26: Line 26:
 
                             0
 
                             0
 
(1/2)*(1/4) = 0 False, DEPENDENT
 
(1/2)*(1/4) = 0 False, DEPENDENT
 +
 +
[[Category:MA375Spring2009Walther]]

Revision as of 09:19, 5 March 2009

6.1 #38

Coin tossed 3 times. Possible Outcomes: TTT HHH TTH HHT THT HTH THH HTT

Are the following independent? ie. p(A intersection B) = p(A)* p(B)

a. First coin tails Second coin heads First coin tails and Second coin heads

        4/8                      4/8                           2/8

(1/2)*(1/2) = 1/4 INDEPENDENT


b. First coin tails Two, and not three heads come up in a row Intersection: First coin tails, and then the last 2 are heads

         4/8                           2/8                                                   1/8

(1/2)*(1/4) = 1/8 INDEPENDENT


c. Second coin tails Two, and not three heads come up in a row

          4/8                               2/8                  

Intersection: Second coin must be tails, and then the last 2 slots must be 2 heads in a row

                           0

(1/2)*(1/4) = 0 False, DEPENDENT

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett