Line 4: Line 4:
  
 
P(H)=0.5
 
P(H)=0.5
P(T)=0.5
+
P(T)=0.5
P(H∩T)=0 (You can't have both H and T in one flip)
+
P(H∩T)=0 (You can't have both H and T in one flip)
  
 
(0.5)*(0.5)≠0
 
(0.5)*(0.5)≠0
  Not independent
+
Not independent

Revision as of 19:07, 4 March 2009

If Independent then P(H)*P(T)=P(H∩T)

Sample Case: One flip of coin

P(H)=0.5

P(T)=0.5
P(H∩T)=0 (You can't have both H and T in one flip)

(0.5)*(0.5)≠0

Not independent

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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood