(New page: If Independent then P(H)*P(T)=P(H<math>union</math>T) Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H<math>union</math>T)=0 (You can't have both H and T in one flip) (0.5)*(0.5)=0 No...)
 
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If Independent then P(H)*P(T)=P(H<math>union</math>T)
+
If Independent then P(H)*P(T)=P(H∩T)
  
 
Sample Case: One flip of coin
 
Sample Case: One flip of coin
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P(H<math>union</math>T)=0 (You can't have both H and T in one flip)
 
P(H<math>union</math>T)=0 (You can't have both H and T in one flip)
  
(0.5)*(0.5)=0
+
(0.5)*(0.5)≠0
 
Not independent
 
Not independent

Revision as of 19:05, 4 March 2009

If Independent then P(H)*P(T)=P(H∩T)

Sample Case: One flip of coin P(H)=0.5 P(T)=0.5 P(H$ union $T)=0 (You can't have both H and T in one flip)

(0.5)*(0.5)≠0 Not independent

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett