Line 9: Line 9:
 
To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.
 
To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.
  
<math>\frac{d}{dp}(p^4(1-p)^6) = 2*p^3(p-1)^5(5p - 2)</math>
+
<math>\frac{d}{dp}(p^4(1-p)^6) = 2p^3(p-1)^5(5p - 2)</math>
  
 
<math>2*p^3(p-1)^5(5p - 2) = 0, p = 2/5</math>
 
<math>2*p^3(p-1)^5(5p - 2) = 0, p = 2/5</math>

Latest revision as of 19:25, 4 November 2008

Let O=TTHHTHTTHT

and knowing p=P[head]

$ P[O;p] = p^4(1-p)^6 $

$ P_{ML}=max(p^4(1-p)^6) $

To find the max of a function one could find the derivative of the function and set the it zero and then solve for the variable that was used in finding the derivative.

$ \frac{d}{dp}(p^4(1-p)^6) = 2p^3(p-1)^5(5p - 2) $

$ 2*p^3(p-1)^5(5p - 2) = 0, p = 2/5 $

Alumni Liaison

Abstract algebra continues the conceptual developments of linear algebra, on an even grander scale.

Dr. Paul Garrett