m
Line 2: Line 2:
  
 
<math>\sqrt(A) cos(2pi*drand48())</math>
 
<math>\sqrt(A) cos(2pi*drand48())</math>
 +
 +
where A is still the exponential RV calculated in 1b.

Revision as of 10:31, 21 October 2008

Regarding Seraj's solution, i believe the solution would be

$ \sqrt(A) cos(2pi*drand48()) $

where A is still the exponential RV calculated in 1b.

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