Difference between revisions of "Daniel Truax ECE302Fall2008sanghavi" - Rhea

Revision as of 10:28, 21 October 2008

Regarding Seraj's solution, i believe the solution would be

$\sqrt(A) cos(2pi*drand48())$

Revision as of 10:28, 21 October 2008 (view source) Dtruax (Talk) (New page: Regarding Seraj's solution, i believe the solution would be <math>\sqrt(A) cos(''2pi*''drand48())</math>)		Revision as of 10:28, 21 October 2008 (view source) Dtruax (Talk) m Newer edit →
Line 1:		Line 1:
	Regarding Seraj's solution, i believe the solution would be		Regarding Seraj's solution, i believe the solution would be

−	<math>\sqrt(A) cos(''2pi*''drand48())</math>	+	<math>\sqrt(A) cos(2pi*drand48())</math>