(New page: The multiplicative set of F of non-zero elements forms a group under multiplication. Since it has n-1 elements it means x^(n-1) = 1 (property of groups -Sarah Liszka) |
|||
| (2 intermediate revisions by 2 users not shown) | |||
| Line 2: | Line 2: | ||
-Sarah Liszka | -Sarah Liszka | ||
| + | |||
| + | |||
| + | Does this work? I was looking and don't we need the group to be cyclic for that to work? | ||
| + | |||
| + | -Allen Jarboe | ||
| + | |||
| + | |||
| + | ---- | ||
| + | Does anyone know how to do this one? | ||
| + | ---- | ||
| + | I don't completely understand this problem. Did somebody understand it well? | ||
| + | |||
| + | -Nate Shafer | ||
Latest revision as of 18:39, 2 November 2008
The multiplicative set of F of non-zero elements forms a group under multiplication. Since it has n-1 elements it means x^(n-1) = 1 (property of groups
-Sarah Liszka
Does this work? I was looking and don't we need the group to be cyclic for that to work?
-Allen Jarboe
Does anyone know how to do this one?
I don't completely understand this problem. Did somebody understand it well?
-Nate Shafer
