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Any body have any ideas???? I'm lost. | Any body have any ideas???? I'm lost. | ||
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| − | I don't know either. I looked in the back of the book, but I don't see how what they're saying has anything to do with the problem. The back of the book is talking about how <math>\phi_{a^{n}}=1</math>, but I thought that we basically needed to show that <math>\phi_{a}^{n}=1</math>. All I can show is that <math>\phi_{a}^{n}=ax^{n}a^{-1}</math>, and that <math>\phi_{a}^{n}=x</math> if G is abelian. | + | I don't know either. I looked in the back of the book, but I don't see how what they're saying has anything to do with the problem. The back of the book is talking about how <math>\phi_{a^{n}}=1</math>, but I thought that we basically needed to show that <math>\phi_{a}^{n}=1</math>. All I can show is that <math>\phi_{a}^{n}(x)=ax^{n}a^{-1}</math>, and that <math>\phi_{a}^{n}(x)=x</math> if G is abelian. |
Revision as of 18:29, 24 September 2008
Any body have any ideas???? I'm lost.
I don't know either. I looked in the back of the book, but I don't see how what they're saying has anything to do with the problem. The back of the book is talking about how $ \phi_{a^{n}}=1 $, but I thought that we basically needed to show that $ \phi_{a}^{n}=1 $. All I can show is that $ \phi_{a}^{n}(x)=ax^{n}a^{-1} $, and that $ \phi_{a}^{n}(x)=x $ if G is abelian.
