(Reconstructing a signal from its samples using Interpolation)
(Reconstructing a signal from its samples using Interpolation)
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-the following equation shows how to take a continuous curve and represent an interpolation formula for an ideal lowpass filter H(jw):
 
-the following equation shows how to take a continuous curve and represent an interpolation formula for an ideal lowpass filter H(jw):
  
<math> h(t) = \frac{wcT sin(wct)}{\piwct} </math>
+
<math> h(t) = \frac{wcT sin(wct)}{\pi*wct} </math>

Revision as of 10:36, 8 November 2008

Reconstructing a signal from its samples using Interpolation

We have learned in class that a signal can be reformed by obtaining multiple samples of its signal and using an important procedure we know as interpolation we can obtain the original signal of the function.

- it is noted that if the sampling instants are sufficiently close, then the signal can be reconstructed using a lowpass filter. the output is then considered to be:

$ xr(t)= xp(t) * h(t) $

or with xp(t):

$ xr(t)= \sum_{n =-\infty}^{\infty} x(nT)h(t-nT) $


-the following equation shows how to take a continuous curve and represent an interpolation formula for an ideal lowpass filter H(jw):

$ h(t) = \frac{wcT sin(wct)}{\pi*wct} $

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