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<math> x(t) = \frac{d}{dt} {u(-2-t) + u(t-2)} </math> | <math> x(t) = \frac{d}{dt} {u(-2-t) + u(t-2)} </math> | ||
| − | <math> | + | <math> X(\omega) = \int_{-\infty}^{\infty} \frac{d}{dt} {u(-2-t) + u(t-2)} e^{-j \omega t} dt </math> |
| + | |||
| + | <math> X(\omega) = \int_{-\infty}^{\infty} \delta (-2-t) e^{-j \omega t} dt + \int_{-\infty}^{\infty} \delta (t-2) e^{-j \omega t} dt</math> | ||
Revision as of 17:21, 24 October 2008
Fourier Transform of delta functions
1.
$ x(t) = \delta (t+1) + \delta (t-1) $
$ X(\omega) = \int_{-\infty}^{\infty} \delta (t+1)e^{-j \omega t} + \int_{-\infty}^{\infty} \delta (t-1)e^{-j \omega t} dt $
$ X(\omega) = e^{j \omega}+ e^{-j \omega} = \frac{1}{2} (e^ {j \omega} + e^ {-j \omega})^2 $
$ X(\omega) = 2cos(\omega) $
2.
$ x(t) = \frac{d}{dt} {u(-2-t) + u(t-2)} $
$ X(\omega) = \int_{-\infty}^{\infty} \frac{d}{dt} {u(-2-t) + u(t-2)} e^{-j \omega t} dt $
$ X(\omega) = \int_{-\infty}^{\infty} \delta (-2-t) e^{-j \omega t} dt + \int_{-\infty}^{\infty} \delta (t-2) e^{-j \omega t} dt $
