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<math> \sum^{-n}_{r=0}2^{-r}, n<=0 </math> | <math> \sum^{-n}_{r=0}2^{-r}, n<=0 </math> | ||
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| + | <math> \sum^{-n}_{r=0}(1/2)^{r}, n<=0 </math> | ||
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0, else | 0, else | ||
Revision as of 09:52, 15 October 2008
question
3. An LTI system has unit impulse response $ h[n]=u[-n] $ Compute the system's response to the input $ x[n]=2^{n}u[-n]. $(Simplify your answer until all \sum signs disappear.)
solution
$ y[n]=x[n]*h[n] $
$ y[n]=\sum^{\infty}_{k=-\infty}x[n]*h[n-k] $
$ y[n]=\sum^{\infty}_{k=-\infty}2^{k}u[-k]u[n-k] $
n[-k] = 1 ,-k>=0
k<=0
$ y[n]=\sum^{0}_{k=-\infty}2^{k}u[n-k] $
$ \sum^{0}_{k=n}2^{k}, n<=0 $
0, else
let r=-k, k=-r
$ \sum^{-n}_{r=0}2^{-r}, n<=0 $
0, else
$ \sum^{-n}_{r=0}(1/2)^{r}, n<=0 $
0, else
