(New page: <math>\sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} </math>) |
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− | <math>\sum_{k=0}^n x^k = \frac{1-x^{n+1}}{1-x} </math> | + | <math>\sum_{k=0}^n x^k = \left\{ \begin{array}{ll} \frac{1-x^{n+1}}{1-x}&, \text{ if } x\neq 1\\ n+1 &, \text{ else}\end{array}\right. </math> |
Latest revision as of 10:20, 1 October 2008
$ \sum_{k=0}^n x^k = \left\{ \begin{array}{ll} \frac{1-x^{n+1}}{1-x}&, \text{ if } x\neq 1\\ n+1 &, \text{ else}\end{array}\right. $