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To help answer this question, I consulted Signals and Systems, Oppenheim Willsky and Nawab.
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Suppose we are given the following information about a signal x(t):
 
Suppose we are given the following information about a signal x(t):
  
1. x(t) is real and even
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1. x(t) is real and even.
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2. x(t) is periodic with period T = 4 and Fourier coefficients <math> \ a_k </math>.
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3. <math> \ a_k = 0 </math> for <math> \left \vert k \right \vert > 1 </math>.
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4. <math> \frac{1}{2}\int_{0}^{2} \left \vert x(t) \right \vert ^2 \, dt = 1 </math>.
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Specify two different signals that satisfy these conditions.
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Two signals that would satisfy these coniditions is the input signal
  
2. x(t) is periodic with period T = 4 and Fourier coefficients <math> a_k </math>
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<math>
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\ x_1(t) = \sqrt{2} cos(2\pi t)
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</math>
  
3.
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and
<math> a_k = 0
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<math>
</math> for <math> stuff </math>
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\ x_2(t) = - \sqrt{2} cos(2\pi t)
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</math>
  
4. <math> stuff2 </math>
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as cos(t) is an even function with a Fourier Series representation that has coefficients of 0 for absolute values of k greater than one. By multiplying the cosine function by the amplitude of the square root of 2 the signal provides the signal power of 1 unit when input into the power equation of specification (4).

Latest revision as of 17:33, 26 September 2008

To help answer this question, I consulted Signals and Systems, Oppenheim Willsky and Nawab.

Suppose we are given the following information about a signal x(t):

1. x(t) is real and even.

2. x(t) is periodic with period T = 4 and Fourier coefficients $ \ a_k $.

3. $ \ a_k = 0 $ for $ \left \vert k \right \vert > 1 $.

4. $ \frac{1}{2}\int_{0}^{2} \left \vert x(t) \right \vert ^2 \, dt = 1 $.

Specify two different signals that satisfy these conditions.

Two signals that would satisfy these coniditions is the input signal

$ \ x_1(t) = \sqrt{2} cos(2\pi t) $

and $ \ x_2(t) = - \sqrt{2} cos(2\pi t) $

as cos(t) is an even function with a Fourier Series representation that has coefficients of 0 for absolute values of k greater than one. By multiplying the cosine function by the amplitude of the square root of 2 the signal provides the signal power of 1 unit when input into the power equation of specification (4).

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