(DT signal & its Fourier Coefficients)
(DT signal & its Fourier Coefficients)
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== DT signal & its Fourier Coefficients ==
 
== DT signal & its Fourier Coefficients ==
  
<math>\ x[n] = 5sin(3 \pi n + \frac{4}{\pi})</math>
+
<math>\ x[n] = 5sin(3 \pi n + \frac{\pi}{4})</math>
  
 
Knowing its Fourier series is
 
Knowing its Fourier series is
  
<math>\ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{4}{\pi})}-e^{-j (3\pi n + \frac{4}{\pi})})
+
<math>\ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{\pi}{4})}-e^{-j (3\pi n + \frac{\pi}{4})})

Revision as of 15:20, 26 September 2008

DT signal & its Fourier Coefficients

$ \ x[n] = 5sin(3 \pi n + \frac{\pi}{4}) $

Knowing its Fourier series is

$ \ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{\pi}{4})}-e^{-j (3\pi n + \frac{\pi}{4})}) $

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To all math majors: "Mathematics is a wonderfully rich subject."

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