Line 8: | Line 8: | ||
<math>y(t) = \int^{\infty}_{-\infty} \delta(t) dt\,</math><br> | <math>y(t) = \int^{\infty}_{-\infty} \delta(t) dt\,</math><br> | ||
<br> | <br> | ||
− | <math>H(s)=\int_{-\infty}^{\infty}h | + | <math>H(s)=\int_{-\infty}^{\infty}h(\tau)e^{-s\tau}</math><br> |
<br> | <br> | ||
<math>H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau}</math><br> | <math>H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau}</math><br> |
Revision as of 07:06, 26 September 2008
Obtain the input impulse response h(t) and the system function H(s) of your system
A very simple system:
$ y(t)=x(t)\, $ and $ x(t)=\delta(t) $
We can get $ h(t)=\delta(t)\, $
$ y(t) = \int^{\infty}_{-\infty} \delta(t) dt\, $
$ H(s)=\int_{-\infty}^{\infty}h(\tau)e^{-s\tau} $
$ H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau} $